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Next: 4.4 APD gain optimization Up: 4 Numerical Capacity Results Previous: 4.2 Data rate vs.

4.3 Optimization of PPM order

Fig. 4 begs the question of what PPM order optimizes the data rate. For nighttime reception in which $ \bar n_b \ll 1$, the optimal PPM order is near $ M=2048$. This closely follows the discussion in Section 2.2.2 regarding the errorless channel. For daytime reception in which $ \bar n_b \approx 100$, we can see from Fig. 4 that the optimal PPM order is well under 256. To be more precise, the order of PPM that maximizes capacity in bits per second can be seen directly from a plot of capacity versus $ M$. This is shown in Fig. 5, and the optimal PPM orders for various values of $ \bar n_b$ are summarized in Table 2.

Figure 5: Capacity of $ M$-PPM on an optical channel, with $ P_b = 10^{-6}$, $ \bar n_s=100$, $ \bar n_b\in\{0.1,1,10,50,100\}$, $ T_s=31.25$ ns, $ T_d = 432000$ ns, and the SLiK APD detector.
\includegraphics[width=5in]{figures/m.eps}




Table 2: Optimal PPM orders $ M$ when $ P_b = 10^{-6}$, $ \bar n_s=100$, $ \bar n_b\in\{0.1,1,10,50,100\}$, $ T_s=31.25$ ns, $ T_d = 432000$ ns, and the SLiK APD detector.
$ \bar n_b$ Optimal $ M$
0.1 2036
1 1815
10 634
50 52
100 18

This suggests use of a multiple PPM order communications system. During nighttime reception it should use $ M$ on the order of thousands, and during daytime reception it should use $ M$ on the order of dozens. Unoptimized PPM orders can be costly. As can be seen from Fig. 5, using $ M=2036$ during the day would be disastrous for the data rate. Using $ M=18$ at night reduces capacity by over half.


next up previous
Next: 4.4 APD gain optimization Up: 4 Numerical Capacity Results Previous: 4.2 Data rate vs.
Jon Hamkins 2000-01-27