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Next: B..3 Case 3 Up: B. Numerical evaluation of Previous: B..1 Case 1

B..2 Case 2

\begin{displaymath}\small J({\mathbf a}) = \left[
\begin{array}{cccccccccc}
37.5...
...46 & 0 & -0.00246 & -0.114 & -1.26e+09
\end{array}\right.\cdots\end{displaymath}

$\displaystyle \cdots\left.\begin{array}{cccccccccc}
-1.49e+07 & -1.38e+08 & -0....
...0 \\
8.47e+05 & 7.86e+06 & 0.000813 & -1.36e-06 & -0.0164
\end{array} \right]$



Jon Hamkins 2000-10-13